Saturday, February 9, 2013

Derivation of De brogle wavelenth

de Broglie relations

Quantum mechanics

The de Broglie equations relate the wavelength λ to the momentum p, and frequency f to the kinetic energy E (excluding its rest energy and any potential energy) of a particle:[2]
\begin{align}
& \lambda = h/p\\
& 
\end{align}
where h is Planck's constant. The equation can be equivalently written as
\begin{align}
& p = \hbar k\\
& E = \hbar \omega\\
\end{align}
using the definitions
In each pair, the second is also referred to as the Planck-Einstein relation, since it was also proposed by Planck and Einstein. E

Special relativity

Using the relativistic momentum formula from special relativity
p = \gamma m_0v
allows the equations to be written as[4]
\begin{align}&\lambda = \frac {h}{\gamma m_0v} = \frac {h}{m_0v} \sqrt{1 - \frac{v^2}{c^2}}\\
& f = \frac{\gamma\,m_0c^2}{h} = \frac {m_0c^2}{h\sqrt{1 - \frac{v^2}{c^2}}}
\end{align}
where m0 is the particle's rest mass, v is the particle's velocity, γ is the Lorentz factor, and c is the speed of light in a vacuum. See group velocity for details of the derivation of the de Broglie relations. Group velocity (equal to the particle's speed) should not be confused with phase velocity (equal to the product of the particle's frequency and its wavelength). In the case of a non-dispersive medium, they happen to be equal, but otherwise they are not.

Four-vectors

Using the four-momentum P = (E/c, p) and the four-wavevector K = (ω/c, k), the De Broglie relations form a single equation:
\mathbf{P}= \hbar\mathbf{K}
which is frame-independent

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